# Question #31f01

##### 1 Answer

#### Explanation:

1.) Make a tally sheet of all atoms involved.

Left Side:

C = 2

H = 4

O = 2 + 2 (DO NOT ADD THIS UP YET)

Right Side:

C = 1

H = 2

O = 2 + 1 (DO NOT ADD THIS UP YET)

2.) Identify the atom that is easiest to balance, in this case, the

Left Side:

C = **2**

H = 4

O = 2 + 2 (DO NOT ADD THIS UP YET)

Right Side:

C = 1 x **2**

H = 2

O = 2 + 1 (DO NOT ADD THIS UP YET)

Since the

Left Side:

C = **2**

H = 4

O = 2 + 2

Right Side:

C = 1 x **2**

H = 2

O = (2 x

3.) Find the next atom that is easy to balance, this time the

Left Side:

C = **2**

H = **4**

O = 2 + 2

Right Side:

C = 1 x 2 = **2**

H = 2 x **4**

O = (2 x 2) + 1

Again, since the

Left Side:

C = **2**

H = **4**

O = 2 + 2 = *4*

Right Side:

C = 1 x 2 = **2**

H = 2 x **4**

O = (2 x 2) + (1 x *6*

4.) Notice now that the only atom left unbalanced is the

For this, please remember that if given a choice, ALWAYS TRY TO BALANCE USING THE SIMPLER MOLECULE FIRST. In this case, the simpler molecule is the

Left Side:

C = **2**

H = **4**

O = 2 + (2 x **6**

Right Side:

C = 1 x 2 = **2**

H = 2 x 2 = **4**

O = (2 x 2) + (1 x 2) = **6**

Final Answer:

The equation is now balanced.