Question #c26b5

1 Answer
Jun 9, 2017

Answer:

The equation of parabola is #y= 3(x-1)^2 -48 #

Explanation:

Lowest point is vertex of the parabola. y-coordinate of vertex is #-48#.

x-coordinate of vertex is mid point of x-intercepts #-3 and 5# i.e #1#. So vertex is at # (1,-48)#

The equation of parabola is #y=a(x-h)^2+k or y=a(x-1)^2 -48#.

The point #(5,0)# is on the parabola , so the point will satisfy the equation. # 0= a(5-1)^2 -48 or 0 = 16a-48 or 16a=48 or a=3#

Hence the equation of parabola is #y= 3(x-1)^2 -48 #.
graph{3(x-1)^2 -48 [-160, 160, -80, 80]} [Ans]