Question #5d302

Mar 15, 2017

I got $\frac{9}{11}$

Explanation:

I would try by using the fact that:
${x}^{\frac{a}{b}} = \sqrt[b]{{x}^{a}}$
and
${x}^{-} a = \frac{1}{x} ^ a$
to write your expression as:

$\frac{\frac{1}{\sqrt{36}}}{\frac{1}{\sqrt{{9}^{3}}} + \frac{1}{\sqrt{36}}} = \frac{\frac{1}{6}}{\frac{1}{27} + \frac{1}{6}} = \frac{\frac{1}{6}}{\frac{2 + 9}{54}} =$

$= \frac{1}{6} \cdot \frac{54}{11} = \frac{9}{11}$