Question

Question #05dd5

Answer 1

`a=3`

Explanation:

`f(x)= (ax^2-1)(3+2x)`

`f(x)= 3ax^2+2ax^3-3-2x`

`f(x)= 2ax^3+3ax^2 -2x-3`

By Differentiating,

`f'(x) = 6ax^2 +6ax-2`

Put `x=1`

`f'(1) = 12a-2`

`34 = 12a-2`

`12a = 36`

`a=3`