How do you find the derivative of $\frac{e^{2 x} - e^{- 2 x}}{e^{2 x} + e^{- 2 x}}$ $(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))$ ?

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How do you find the derivative of $\frac{e^{2 x} - e^{- 2 x}}{e^{2 x} + e^{- 2 x}}$ $(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))$ ?

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Answer 1 · 2015-02-25T18:32:24

I would use the Quotient Rule:
$y = \frac{f (x)}{g (x)}$ $y=f(x)/g(x)$ then $y'=(f'(x)g(x)-f(x)g'(x))/[g(x)]^2$
In your case you get:
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How do you find the derivative of $\frac{e^{2 x} - e^{- 2 x}}{e^{2 x} + e^{- 2 x}}$ $(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))$ ?

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How do you find the derivative of $\frac{e^{2 x} - e^{- 2 x}}{e^{2 x} + e^{- 2 x}}$ $(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))$ ?