Question #5fd0d

1 Answer
Dec 28, 2017

Answer:

The speed is #=6.4ms^-1#. The flow rate is #=16.29m^3h^-1#

Explanation:

The flow rate #Q# is constant

#Q=v_1A_1=v_2A_2#

The speed #v_1=1.6ms^-1#

The cross section area #A_1=pid_1^2/4=pi*(0.06)^4/4m^2#

The cross section #A_2=pid_2^2/4=pi*0.03^2/4 m^2#

#pi*0.06^2/4*1.6=pi0.03^2/4*v_2#

#v_2=0.06^2/0.03^2*1.6=6.4ms^1#

The flow rate is

#Q=pi*0.06^2/4*1.6=0.0045m^3s^-1=16.29m^3h^-1#