# Question #ef3fa

##### 1 Answer

1) Heat (J) =

2) Heat (J) =

#### Explanation:

In both cases the water is in the liquid phase, so no phase transition enthalpy is needed. In both directions you simply need to apply the heat capacity of water to the temperature difference of the volume. The Liquid Specific Heat of water is

For the temperature ranges of this problem a reasonable approximation of the mass is 1g/mL, so we have 20.0 g of water. The temperature change is

Getting our equation set up dimensionally to ensure a correct answer, we have:

1) Heat (J) =

2) Heat (J) =