# Question #84631

Mar 14, 2017

$\text{80. g}$

#### Explanation:

Since sodium hydroxide is a strong base and hydrochloric acid is a strong acid, they both completely dissociate when dissolved in water.

In a strong acid-strong base reaction, the moles of hydrogen ions must equal the moles of hydroxide ions in order to create a neutral solution.

$\text{HCl" + "NaOH" -> "NaCl" + "H"_2"O}$

Divide the $\text{73 g}$ of $\text{HCl}$ by its molar mass of $\text{36.46 g/mol}$ to convert that value to moles

$\text{73 g"/"36.46 g/mol" = "2.002 moles}$

Then, using the fact that the moles of hydrochloric acid equal the moles of sodium hydroxide, we know that there are $2.002$ moles of $\text{NaOH}$.

We would multiply that $2.002$ by the molar mass of $\text{NaOH}$ of $\text{39.997 g/mol}$ to get

$\text{2.002 moles" * "39.997 g/mol" = "80. g NaOH}$