How do you simplify #(d^2 + 4d + 3)/(d + 1)#?

1 Answer
smendyka
Mar 16, 2017

See the entire solution process below:

Explanation:

First, factor the numerator as:

#((d + 3)(d + 1))/(d + 1)#

Now, cancel common terms in the numerator and denominator:

#((d + 3)color(red)(cancel(color(black)((d + 1)))))/color(red)(cancel(color(black)(d + 1))) ->#

#d + 3# Where: #d + 1 != 0# or #d != -1#

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