Find #x# if #log(3x+5)=2#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Shwetank Mauria Mar 16, 2017 #x=31 2/3# Explanation: As #log(3x+5)=2# #3x+5=10^2=100# i.e. #3x=100-5=95# and #x=95/3=31 2/3# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 4901 views around the world You can reuse this answer Creative Commons License