Question #a0503

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Answer 1 · 2017-03-19T19:55:56

(#sqrt3, 1#)

To make this change, we will use two equations:

#x=rcos(theta)# and #y=rsin(theta)#

Our polar coordinate point is written in the form

#(r, theta)#

So for the x coordinate we will plug in r and #theta# into the x equation

#x=(-2)(cos((7pi)/6)) = (-2)(-sqrt3/2) = sqrt3#

We will do the same for the y coordinate by plugging in the point values to the y equation

#y=(-2)(sin((7pi)/6)) = (-2)(-1/2) = 1#

And we take those values and write them as a point

#(sqrt3, 1)#