Question

Question #a0503

Answer 1

(`sqrt3, 1`)

Explanation:

To make this change, we will use two equations:

`x=rcos(theta)` and `y=rsin(theta)`

Our polar coordinate point is written in the form

`(r, theta)`

So for the x coordinate we will plug in r and `theta` into the x equation

`x=(-2)(cos((7pi)/6)) = (-2)(-sqrt3/2) = sqrt3`

We will do the same for the y coordinate by plugging in the point values to the y equation

`y=(-2)(sin((7pi)/6)) = (-2)(-1/2) = 1`

And we take those values and write them as a point

`(sqrt3, 1)`