# Question 96a4f

Mar 25, 2017

The empirical formula is ${\text{CuS}}_{2}$.

#### Explanation:

An empirical formula is the simplest whole number molar ratio of the elements in a compound.

Your compound contains $\text{0.768 mol Cu}$ and $\text{1.56 mol S}$.

I like to summarize the calculations in a table.

$\boldsymbol{\text{Element"color(white)(m) "Moles"color(white)(m) "Ratio"color(white)(m)color(white)(l)"Integers}}$
color(white)(m)"Cu" color(white)(mmmll)0.768 color(white)(Xm)1color(white)(mmmmmll)1#
$\textcolor{w h i t e}{m} \text{S"color(white)(mmmml)1.56} \textcolor{w h i t e}{X m l l} 2.03 \textcolor{w h i t e}{m m m m l} 2$

There is 1 mol of $\text{Cu}$ for 2 mol of $\text{S}$.

The empirical formula is ${\text{CuS}}_{2}$.