Question

Question #1a6bb

Answer 1

Relation is great.

Explanation:

Suppose,a particle of mass `m_1` moving with a velocity of `u_1` collides with a particle of mass`m_2` moving with a velocity `u_2`.
After collision the speed of the mass `m_1` and`m_2` are respectively `v_1` and `v_2`.

Let,the `m_1` particle pushes the other with the force`F_(1->2)` and the `m_2` particle on `m_1` is `F_(2->1`.
According to Newton's third law,
`F_(1->2)=-F_(2->1)`
As we know impulse of force is equal to change of momentum ,so we can write
`F_(1->2)=m_1u_1-m_1v_1`
`F_(2->1)=m_2u_2-m_2v_2`
Solving all equations,
`m_1u_1-m_1v_1=-m_2u_2+m_2v_2`
`=>m_1u_1+m_2u_2=m_1v_1+m_2v_2`
That's the all.