Question #c18bc

1 Answer
Ernest Z.
Jul 31, 2017

The concentrations in the 10X running buffer are #"A) [Tris] = 0.250 mol/L"; "B) [Gly] = 1.92 mol/L"; "C) [SDS] = 1 % (m/v)"#.

Explanation:

A) Tris

#"Moles of Tris" = 6.06 color(red)(cancel(color(black)("g Tris"))) × "1 mol Tris"/(121.14 color(red)(cancel(color(black)("g Tris")))) = "0.050 02 mol"#

#"[Tris]" = "0.050 02 mol"/"0.200 L" = "0.250 mol/L"#

B) Glycine

#"Moles of Gly" = 28.8 color(red)(cancel(color(black)("g Gly"))) × "1 mol Gly"/(75.1 color(red)(cancel(color(black)("g Gly")))) = "0.3835 mol"#

#"[Tris]" = "0.3835 mol"/"0.200 L" = "1.92 mol/L"#

C) SDS

#"[SDS]" = "2 g"/"200 mL" × 100 % = "1 % (m/v)"#

Related questions
See all questions in Buffer Calculations
Impact of this question
1496 views around the world
You can reuse this answer
Creative Commons License