Question #c373d

1 Answer
Mar 22, 2017

Answer:

Here is the equation:
#C_2H_4 + 3O_2 rarr 2CO_2 + 2H_2O#

Other solutions follow...

Explanation:

In the equation, we see that each one mole of #C_2H_4# results in two moles of #CO_2#. THis establishes the ratio between these compounds. So, 0.02 mole of #C_2H_4# must yield 0.04 mol of #CO_2#

Since the molar mass of #CO_2# is 44.0 g, the mass of 0.04 mol is
#0.04 xx 44.0 = 1.76 g#

The volume of the gas at r.t.p. (can I assume this is room temperature of 25°C?) is found by multiplying by the molar volume of a gas at 25°C, namely 24.5 L

#0.04 "mol" xx 24.5 L/"mol" = 0.98 L#