# Question #c373d

Mar 22, 2017

Here is the equation:
${C}_{2} {H}_{4} + 3 {O}_{2} \rightarrow 2 C {O}_{2} + 2 {H}_{2} O$

Other solutions follow...

#### Explanation:

In the equation, we see that each one mole of ${C}_{2} {H}_{4}$ results in two moles of $C {O}_{2}$. THis establishes the ratio between these compounds. So, 0.02 mole of ${C}_{2} {H}_{4}$ must yield 0.04 mol of $C {O}_{2}$

Since the molar mass of $C {O}_{2}$ is 44.0 g, the mass of 0.04 mol is
$0.04 \times 44.0 = 1.76 g$

The volume of the gas at r.t.p. (can I assume this is room temperature of 25°C?) is found by multiplying by the molar volume of a gas at 25°C, namely 24.5 L

$0.04 \text{mol" xx 24.5 L/"mol} = 0.98 L$