Question #bdced

Mar 23, 2017

$T = 2 g N , \text{ & } a = \frac{g}{3} m {s}^{- 2}$

Explanation:

we use Newton's 2nd law on both particles and solve the

eqns simultaneously

$\ast {m}_{1} \ast$

$T = 6 a$

$\ast {m}_{2} \ast$

$3 g - T = 3 a$

substitute for $T$

$3 g - 6 a = 3 a$

$9 a = 3 g$

$a = \frac{g}{3} m {s}^{- 2}$

$\therefore T = 6 \times \frac{g}{3} = 2 g N$