Question

Question #61ed8

Answer 1

`LHS=tan^-1 (1) + 2tan^-1 (1/4)`

`=tan^-1 (1) + tan^-1 ((1/4+1/4)/(1-1/4^2))`

`=tan^-1 (1) + tan^-1 ((1/2)/(15/16))`

`=tan^-1 (1) + tan^-1 (8/15)`

`=tan^-1 ((1 +8/15)/(1-1xx8/15))`

`=tan^-1 ((23/15)/(7/15))`

`=tan^-1 (23/7)=RHS`