Question

Question #0def0

Answer 1

`50.1 kJ`

Explanation:

We have two different heat inputs to calculate – the phase transition from ice to water at 0’C and then the heating of the liquid water from 0 to 70’C.
Liquid Specific Heat: `4.178 J/(g-^oK)` ; Heat of Fusion: 333.55 J/g#

`80.0g * 333.55 J/g + 80.0g * ((70-0)^oC) * 4.178 J/(g-^oC)`

`26684 J + 23397 J = 50081 "Joules", or 50. 1 kJ`

A good example of this type of problem is explained at the Khan Academy here:
https://www.khanacademy.org/science/chemistry/states-of-matter-and-intermolecular-forces/states-of-matter/v/specific-heat-heat-of-fusion-and-vaporization