Question #0def0

1 Answer
Mar 26, 2017

Answer:

#50.1 kJ#

Explanation:

We have two different heat inputs to calculate – the phase transition from ice to water at 0’C and then the heating of the liquid water from 0 to 70’C.
Liquid Specific Heat: #4.178 J/(g-^oK)# ; Heat of Fusion: 333.55 J/g#

#80.0g * 333.55 J/g + 80.0g * ((70-0)^oC) * 4.178 J/(g-^oC) #

#26684 J + 23397 J = 50081 "Joules", or 50. 1 kJ#

A good example of this type of problem is explained at the Khan Academy here:
https://www.khanacademy.org/science/chemistry/states-of-matter-and-intermolecular-forces/states-of-matter/v/specific-heat-heat-of-fusion-and-vaporization