# Question 0def0

Mar 26, 2017

$50.1 k J$

#### Explanation:

We have two different heat inputs to calculate – the phase transition from ice to water at 0’C and then the heating of the liquid water from 0 to 70’C.
Liquid Specific Heat: $4.178 \frac{J}{g {-}^{o} K}$ ; Heat of Fusion: 333.55 J/g

$80.0 g \cdot 333.55 \frac{J}{g} + 80.0 g \cdot \left({\left(70 - 0\right)}^{o} C\right) \cdot 4.178 \frac{J}{g {-}^{o} C}$

$26684 J + 23397 J = 50081 \text{Joules} , \mathmr{and} 50. 1 k J$

A good example of this type of problem is explained at the Khan Academy here: