# Question #4ec08

Mar 24, 2017

$5 {a}^{4}$

#### Explanation:

distribute the power of $2$ to the $\sqrt{5} {a}^{2}$

${\left(\sqrt{5} {a}^{2}\right)}^{2}$ which gives:

${\left(\sqrt{5}\right)}^{2}$ and ${\left({a}^{2}\right)}^{2}$

$\left(\sqrt{5}\right) \left(\sqrt{5}\right) {a}^{2} {a}^{2}$

$\sqrt{25}$ and ${a}^{4}$

$\sqrt{25}$ goes to $5$

so $5 \cdot {a}^{4}$