Question #00441

1 Answer
Mar 25, 2017

cos(x - pi/6)=(sqrt3)cosx

=>cosx cos(pi/6+sinxsin(pi/6)=(sqrt3)cosx

=>cosx (sqrt3/2)+sinx(1/2)=(sqrt3)cosx

=> sqrt3cosx+sinx=(2sqrt3)cosx

=> sinx=(2sqrt3)cosx-sqrt3cosx

=> sinx=sqrt3cosx

=> sinx/cosx=sqrt3

=> tanx=tan(pi/3)

=>x= npi+pi/3" where " n in ZZ