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Answer 1 · 2017-03-26T08:18:25

#x=-2+-sqrt29#

#50/x+2=2x+10#

First, you would exclude the solution #x=0# and then multiply all the terms by x:

#x!=0# and #50+2x=2x^2+10x#

Then get it in the standard form and solve it by the quadratic formula:

#2x^2+8x-50=0# or, dividing all the terms by 2:

#x^2+4x-25=0#

#x=-2+-sqrt(4+25)# (simplified formula #x=-b/2+-sqrt((b/2)^2-c)#)

#x=-2+-sqrt29#