# Question 5d6a1

Sep 20, 2017

$= P \left(- 1 , 0\right) , L \left(0 , 1\right) , A \left(1 , 1\right) , T \left(0 , 0\right)$

#### Explanation:

A translation of $\left(x + 1 , y\right)$ means for all cooridnates stated, move 1 unit forward on the $x$ axis, and 0 units forward on the $y$ axis. The cooridnates given are $P \left(- 2 , 0\right) , L \left(- 1 , 1\right) , A \left(0 , 1\right) , T \left(- 1 , 0\right)$. If I add 1 on the $x$-axis of $P$, I get

$\left(- 2 + 1 , 0\right) = \left(- 1 , 0\right)$, therefore $\left(- 1 , 0\right)$ is the new $P$ coordinate. I then do the same thing to
$L \left(- 1 + 1 , 1\right) = \left(0 , 1\right)$
$A \left(0 + 1 , 1\right) = \left(1 , 1\right)$, and
$T \left(- 1 + 1 , 0\right) = \left(0 , 0\right)$.

Therfore, the new cooridnates of PLAT are P(-1,0), L(0,1), A(1,1) and T(0,0#. These new coordinates are the same shape, only shifted 1 unit forward in the $x$-direction.

I hope I helped!