Question #792eb

1 Answer
Mark C.
Jan 7, 2018

Yes, but only because wavenumber, #bar(nu)# is #1/lambda# so they are linked via the wave equation.

Explanation:

We know #v = f xx lambda# so #bar(nu) = f/v#

Thus if you alter the frequency, #f# the wavenumber, #bar(nu)# will alter in direct proportion.

Related questions
See all questions in Wave Properties
Impact of this question
1755 views around the world
You can reuse this answer
Creative Commons License