A #0.20*g# mass of gas occupies a #0.200*L# volume at one atmosphere, and #300*K#. What is the molar mass of the gas?

1 Answer
Mar 26, 2017

Answer:

#"Molar mass"# #=# #24.6*g*mol^-1#

Explanation:

We use the Ideal Gas Equation.......

#PV=nRT#

And thus #n="Mass"/"Molar Mass"=(PV)/(RT)#

And so, #"Molar Mass"=("Mass"xxRT)/(PV)#

#=(0.20*gxx0.0821*cancelL*cancel(atm)*cancel(K^-1)*mol^-1xx300*cancelK)/(1*cancel(atm)xx0.200*cancelL)#

#=24.6*g*mol^-1#. I think this is dimensionally correct, however, it does not correspond to a gas I can think of right now.........