Question #1b237

1 Answer
Mar 27, 2017

Use #cos(2x) = 1-2sin^2x# to rewrite.

Explanation:

#sin^2x = 1/2(1-cos(2x))#
(this is called a Power Reduction Formula)

So,

# int sin^2x dx = 1/2int (1-cos(2x)) dx#

We can integrate #intcos(2x) dx# by substitution #u = 2x#

so #intcos(2x) dx = 1/2sin(2x) +C# (check this answer by differentiation)

# int sin^2x dx = 1/2int (1-cos(2x)) dx#

# = 1/2(x-1/2sin(2x))+C#

Rewrite to taste.

You may like

# = 1/2x-1/4sin(2x)+C#

or

# = 1/4(2x-sin(2x))+C#