Question #1b237
1 Answer
Mar 27, 2017
Use
Explanation:
(this is called a Power Reduction Formula)
So,
We can integrate
so
# = 1/2(x-1/2sin(2x))+C#
Rewrite to taste.
You may like
# = 1/2x-1/4sin(2x)+C#
or
# = 1/4(2x-sin(2x))+C#