What is #(25 xx 5)^(1/3)#?

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Answer 1 · 2017-03-29T04:13:51

#(5xx5xx5)^(1/3)=5#

I'm reading this as

#(25xx5)^(1/3)#

We can rewrite this as:

#(5xx5xx5)^(1/3)#

Remember that just as with, say #sqrt4=4^(1/2)=(2xx2)^(1/2)=2#, we can do the same thing here with the cube root:

#(5xx5xx5)^(1/3)=5#

Answer 2 · 2017-03-29T04:20:07

#5#

Expression #=(25 xx 5)^(1/3) =root3 (125)#

In solving roots of integers it is often useful to express the integer as the product of its prime factors.

Here: #125 = 5xx5xx5#

So: #root3 125 = root3 (5 xx 5 xx 5)#

Since #5# occurs three times we may take it through the root sign.

Hence: #root3 125 =5#