Question #91cd0

1 Answer
Mar 30, 2017

#theta = (7pi)/4+k * 2picolor(white)("XX")orcolor(white)("XX")theta =(5pi)/4+ k * 2pi#
#color(white)("XXXXXX") AAk in ZZ#

Explanation:

Given
#color(white)("XXX")sin(theta)+sqrt(2)=-sin(theta)#

#rarrcolor(white)("XXX")2sin(theta) = -sqrt(2)#

#rarrcolor(white)("XXX")sin(theta) = -sqrt(2)/2#

For #theta in [-pi/2,+pi/2]#
#rarrcolor(white)("XXX")theta=-pi/4 (or -45^@)#

For #theta in [0,2pi)#
#rarrcolor(white)("XXX")theta = (7pi)/4 or (5pi)/4#

For #theta# unrestricted, we need to allow for integer multiples of full circles:
#color(white)("XXX")theta = (7pi)/4+ k * 2pi or (5pi)/4 + k * 2pi#
#color(white)("XXXXXXXXX")#for any integer value #k#