Question #e845d

1 Answer
Aditya Banerjee.
Apr 2, 2017

#27.1g# of #CaO# contains #2.92# x #10^23#molecules.

Explanation:

This is a problem of stoichiometry.

The molar mass of #CaO = 40+16 #grams, i.e. #56# grams.

Now, the Avogadro number #=6.023x10^23#.

So, #56g# of #CaO# contains #6.023# x #10^23# molecules.

#:.27.1g# of #CaO# contains #2.92# x #10^23#molecules. (Answer).

Hope it Helps :)

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