m/v % = 2.1 %;
The formula for mass/volume percent is
#color(blue)(bar(ul(|color(white)(a/a)"m/v %" = "mass of solute (g)"/"volume of solution (mL)" × 100 %color(white)(a/a)|)))" "#
The formula for molarity is
#color(blue)(bar(ul(|color(white)(a/a)"Molarity" = "moles"/"litres"color(white)(a/a)|)))" "#
#c = n/V#
The molar mass of glucose (
The formula for molality is
#color(blue)(bar(ul(|color(white)(a/a)"Molality" = "moles of solute"/"kilograms of solvent"color(white)(a/a)|)))" "#
The density of the solution is slightly greater than that of pure water because of the dissolved sugar.
You don’t give a value for the density, so I shall assume a value of 1.008 g/mL.
The mass of 1 L of solution is
We know that 1 L of solution contains 21 g or 0.12 mol of glucose, so
∴ The molality
An osmole is the number of moles solute particles of solute that contribute to the osmotic pressure of a solution.
Osmolality is the number of osmoles in 1 kg of solvent.
Singe glucose does not dissociate in solution, the number of osmoles is the same as the number of moles.