# Question #988dd

Apr 2, 2017

$Z n C {l}_{2} + N {a}_{2} C {O}_{3} \rightarrow Z n C {O}_{3} + 2 N a C l$

#### Explanation:

$Z n C {l}_{2} + N {a}_{2} C {O}_{3} \rightarrow Z n C {O}_{3} + N a C l$

This is what I do...
I write that all elements on the reactant side as well as those on the product side. Not forgetting to split them when there is an addition.

Reactants

$Z n = 1$
$C l = 2$
$+$
$N a = 2$
$C = 1$
$O = 3$

Products

$Z n = 1$
$C = 1$
$O = 3$
$+$
$N a = 1 \times \textcolor{red}{2} = 2$
$C l = 1 \times \textcolor{red}{2} = 2$

From the above, we see that $N a$ is $2$ on the reactant side and $1$ on the product side so we multiply by $\textcolor{red}{2}$ to make it equal. When you do this, it automatically affects $C l$ because it forms a compound.

Check to see if all elements are balanced then rewrite the equation.

$Z n C {l}_{2} + N {a}_{2} C {O}_{3} \rightarrow Z n C {O}_{3} + \textcolor{red}{2} N a C l$