# Question #ffcee

Apr 10, 2017

97.3%

#### Explanation:

Given the two masses, the density is irrelevant to the calculation.
M.W. $H N {O}_{3}$ = 63 kg/kmol. M.W. ${H}_{2} O$ = 18 kg/kmol
Mole percent = moles solute/(moles solvent + moles solute)
125 kg $H N {O}_{3}$ = 1.98 kmol ; 1 kg ${H}_{2} O$ = 0.0556 kmol

Mole percent = 1.98/(0.0556 + 1.98) = 0.973, or 97.3% $H N {O}_{3}$