Question #104ce

1 Answer
Apr 4, 2017

y^2=3sqrt(x^2+y^2)+3x-x^2

Explanation:

Use the following formulas (given by Pythagorean theorem, definition of sine, and definition of cosine, respectively):
color(blue)(x^2+y^2=r^2)
color(blue)(y=rsintheta)
color(blue)(x=rcostheta)

We have to manipulate the equation so that it is possible to substitute the formulas in.

(Note that the graph of r=3+3costheta is a cardioid, which is not a conic section, so the rectangular form of the equation will not be in any standard form.)

r=3+3costheta

color(blue)(r^2)=3r+3color(blue)(rcostheta)

x^2+y^2=3sqrt(x^2+y^2)+3x

y^2=3sqrt(x^2+y^2)+3x-x^2

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