Question #3b535

1 Answer
Apr 18, 2017

Answer:

#2.16×10^-20J#

Explanation:

Energy given to each #"I"_2# molecule through one quantum of radiation#E=(hc)/λ#
where #h# is Planck's Constant, #c# is velocity of light in vacuum and #lambda# wave length of light quantum.

Inserting various values we get
#E=(6.626×10^-34×3×10^8)/(4500×10^-10)#
#⇒E=4.417×10^-19J#

We know that one mole of #"I"_2# molecule#=#Avogadro's number.
#:.#Energy used for breaking up of each #"I"_2# molecule#=(2.4×10^3)/(6.023×10^23)#
#=3.984×10^-19J#

Balance energy is used in imparting kinetic energy to two Iodine atoms#E_b=(4.417-3.984)×10^-19J#
Kinetic energy of each Iodine atom #E_b/2=(4.417−3.984)/2×10^-19#
#=2.16×10^-20J#