Question

Question #3157d

Answer 1

`tan theta = - (1/3)`

Explanation:

Given `- cos^2 theta = 3 sin theta * cos theta`

`- cos theta * cancel(cos theta )= 3 sin theta * cancel (cos theta)`

`- (cos theta/ sin theta) = 3`

`cos theta / sin theta = -3`

`sin theta / cos theta = -(1/3)`

`tan theta = - (1/3)`