Question #ee1e7
1 Answer
Explanation:
All you have to do here is use the molarities and the volumes of the two solutions to figure out how many moles of each reactant were needed for a complete reaction.
For substance
#20 color(red)(cancel(color(black)("cm"^3))) * (1 color(red)(cancel(color(black)("dm"^3))))/(10^3color(red)(cancel(color(black)("cm"^3)))) * "1.5 moles X"/(1color(red)(cancel(color(black)("dm"^3)))) = "0.03 moles X"#
For substance
#10 color(red)(cancel(color(black)("cm"^3))) * (1 color(red)(cancel(color(black)("dm"^3))))/(10^3color(red)(cancel(color(black)("cm"^3)))) * "1 mole Y"/(1color(red)(cancel(color(black)("dm"^3)))) = "0.01 moles Y"#
You can thus say that the two reactants will react in a
#"0.03 moles X"/"0.01 moles Y" = (3 * color(red)(cancel(color(black)(10^(2))))color(white)(.)"moles X")/(1 * color(red)(cancel(color(black)(10^(2))))color(white)(.)"moles Y") = "3 moles X"/"1 mole Y"#
The balanced chemical equation that will describe your reaction can be written as
#3"X"_ ((aq)) + "Y"_ ((aq)) -> "products"#
Therefore, you can say that