Question #a8879 Calculus Power Series Constructing a Maclaurin Series 1 Answer Anjali G Apr 6, 2017 A formula to memorize is the MacLaurin series of #ln(1+x)#. #ln(1+x)=sum_(n=0)^(oo)frac{(-1)^n(x)^(n+1)}{n+1}# Therefore: #ln(1+4x)=sum_(n=0)^oofrac{(-1)^n(4x)^(n+1)}{n+1}# #=sum_(n=0)^oofrac{(-1)^n(4)^(n+1)(x)^(n+1)}{n+1}# Answer link Related questions How do you find the Maclaurin series of #f(x)=(1-x)^-2# ? How do you find the Maclaurin series of #f(x)=cos(x^2)# ? How do you find the Maclaurin series of #f(x)=cosh(x)# ? How do you find the Maclaurin series of #f(x)=cos(x)# ? How do you find the Maclaurin series of #f(x)=e^(-2x)# ? How do you find the Maclaurin series of #f(x)=e^x# ? How do you find the Maclaurin series of #f(x)=ln(1+x)# ? How do you find the Maclaurin series of #f(x)=ln(1+x^2)# ? How do you find the Maclaurin series of #f(x)=sin(x)# ? How do you use a Maclaurin series to find the derivative of a function? See all questions in Constructing a Maclaurin Series Impact of this question 2092 views around the world You can reuse this answer Creative Commons License