What is #1.9791666...# as a fraction ?

1 Answer
Apr 9, 2017

#95/48#

Explanation:

First let me introduce you to some notation in case you have not met it. When a decimal representation repeats, you can write it using a bar over the repeating digits to indicate that they repeat.

So for our example:

#1.979166666... = 1.9791bar(6)#

Departing from my usual method for such problems, first note that:

#2/3 = 0.bar(6)#

So let us try to simplify the given decimal, by mutiplying by #3# first.

#color(blue)(3)*1.9791bar(6) = 5.9375#

Since this ends with a digit #5#, multiply by #2# to find:

#color(blue)(2)*5.9375 = 11.875#

Since this ends with a digit #5#, multiply by #2# to find:

#color(blue)(2)*11/875 = 23.75#

Since this ends with a digit #5#, multiply by #2# to find:

#color(blue)(2)*23.75 = 47.5#

Since this ends with a digit #5#, multiply by #2# to find:

#color(blue)(2)*47.5 = 95#

Collecting the multipliers we used, we have:

#95 = 2*2*2*2*3*1.9791bar(6) = 48*1.9791bar(6)#

Dividing both ends by #48#, we find:

#1.9791bar(6) = 95/48#

Due to the way we found this, we have introduced no common factors, so this is automatically in lowest terms.