What is #1.9791666...# as a fraction ?
1 Answer
Explanation:
First let me introduce you to some notation in case you have not met it. When a decimal representation repeats, you can write it using a bar over the repeating digits to indicate that they repeat.
So for our example:
#1.979166666... = 1.9791bar(6)#
Departing from my usual method for such problems, first note that:
#2/3 = 0.bar(6)#
So let us try to simplify the given decimal, by mutiplying by
#color(blue)(3)*1.9791bar(6) = 5.9375#
Since this ends with a digit
#color(blue)(2)*5.9375 = 11.875#
Since this ends with a digit
#color(blue)(2)*11/875 = 23.75#
Since this ends with a digit
#color(blue)(2)*23.75 = 47.5#
Since this ends with a digit
#color(blue)(2)*47.5 = 95#
Collecting the multipliers we used, we have:
#95 = 2*2*2*2*3*1.9791bar(6) = 48*1.9791bar(6)#
Dividing both ends by
#1.9791bar(6) = 95/48#
Due to the way we found this, we have introduced no common factors, so this is automatically in lowest terms.