# Question f826d

Apr 7, 2017

I got: $- 6.3 \frac{m}{s} ^ 2$

#### Explanation:

We can use the general relationship from Kinematics:
${v}_{f} = {v}_{i} + a t$
Where:
${v}_{f} = 0$ is the final velocity;
${v}_{i} = 38 \frac{m}{s}$ is the initial velocity;
$t = 6 s$ is time;
a=?# is the acceleration.

We get:

$0 = 38 + 6 a$

$a = - \frac{38}{6} = - 6.3 \frac{m}{s} ^ 2$

Where the minus sign tells us that this acceleration opposes the motion reducing continuously the velocity until the object stops.