What mass of copper(II) chloride is required to prepare sodium chloride from a #3.65*g# mass of sodium metal?

1 Answer
Apr 8, 2017

Answer:

Approx. #4*g# of #"copper salt"# are required.......

Explanation:

We have a molar quantity of #(3.65*g)/(58.44*g*mol^-1)=0.0625*mol# with respect to #NaCl#.

There is thus a molar quantity of #0.0625*mol# with respect to the chloride ion? Agreed.

And thus we need a #1/2*"equivalent"# of #"cupric chloride"#, because by composition, each mole of #CuCl_2# supplies 2 moles of chloride ion...........

So thus we need #1/2xx0.0625*molxx134.45*g*mol^-1#

#=4.20*g# #CuCl_2# to supply the chloride ions.