# What mass of copper(II) chloride is required to prepare sodium chloride from a 3.65*g mass of sodium metal?

Apr 8, 2017

Approx. $4 \cdot g$ of $\text{copper salt}$ are required.......

#### Explanation:

We have a molar quantity of $\frac{3.65 \cdot g}{58.44 \cdot g \cdot m o {l}^{-} 1} = 0.0625 \cdot m o l$ with respect to $N a C l$.

There is thus a molar quantity of $0.0625 \cdot m o l$ with respect to the chloride ion? Agreed.

And thus we need a $\frac{1}{2} \cdot \text{equivalent}$ of $\text{cupric chloride}$, because by composition, each mole of $C u C {l}_{2}$ supplies 2 moles of chloride ion...........

So thus we need $\frac{1}{2} \times 0.0625 \cdot m o l \times 134.45 \cdot g \cdot m o {l}^{-} 1$

$= 4.20 \cdot g$ $C u C {l}_{2}$ to supply the chloride ions.