# Question 05f79

Apr 7, 2017

${a}^{- 5} = \frac{1}{a} ^ 5$

#### Explanation:

Use the exponent rules (x^m)^n = x^(m*n) " and " x^m x^n = x^(m-n)#

${a}^{4} / {\left({a}^{3}\right)}^{3} = {a}^{4} / {a}^{9} = {a}^{4 - 9} = {a}^{-} 5$

When you have a negative exponent in the numerator, you can move the exponent to the denominator and make it positive ${x}^{- m} = \frac{1}{x} ^ m$

This means ${a}^{-} 5 = \frac{1}{a} ^ 5$