Question

Question #05f79

Answer 1

`a^(-5) = 1/a^5`

Explanation:

Use the exponent rules #(x^m)^n = x^(m*n) " and " x^m x^n = x^(m-n)#

`a^4/(a^3)^3 = a^4/a^9 = a^(4-9) = a^-5`

When you have a negative exponent in the numerator, you can move the exponent to the denominator and make it positive `x^(-m) = 1/x^m`

This means `a^-5 = 1/a^5`