Question

Question #617a1

Answer 1

Answer rounded to appropriate (3 ) sig figs: 388 Kelvin or 115 Celsius

Explanation:

PV=nRT
P= pressure in atm
V= volume in liters
n= mols of substance
R= gas constant (.08206 L atm/ K mols
T= temperature in Kelvin
we solve for T as a variable

T=PV/nR
T=`[(1.86)(85.11)] / [(4.97)(.08206)]`= 388.155 K

388 Kelvin or 115 Celsius