Question #935d4

1 Answer
Apr 9, 2017

Answer:

#(2x^3y^3)/(6x^-4y^4) = x^7/(3y)#

Explanation:

Given: #(2x^3y^3)/(6x^-4y^4)#

We can see the integer multipliers: #2/6=1/3#

The #x# component is #x^3/x^-4= x^3/(1/x^4)=x^7# #->#after invert and multiply

The #y# component is #y^3/y^4=1/y# #->#dividing exponents = subtract

Then we can multiply all the components:

#(2x^3y^3)/(6x^-4y^4) = (1/3)x^7(1/y) = x^7/(3y)#