Question #3d416

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Answer 1 · 2017-04-14T17:16:03

Here's what I get.

Quantum numbers

(a) 3 0 0

$n = 3$ tells you that this is the third energy level and $l=0$ tells that it is an $"s"$ orbtal.

Together they tell you that this is a $"3s"$ electron.

(b) 2 1 1

The principal quantum number $n = 2$ tells you that this is the second energy level and $l = 1$ tells you that it is a $"p"$ orbital.

Together they tell you that this is a $"2p"$ electron.

The magnetic quantum number $m_l = 1$ tells you the orientation of the orbital in a magnetic field.

Thus the electron is in one of the three $"3p"$ orbitals.

(c) 4 2- 1

Impossible! You cannot have $l = "-2"$ .

The allowed values go from $l = 0$ to $n-1$ (i.e. $l = 0, 1, 2, 3$ )

(d) 3 3 2

Impossible! You cannot have $l = "3"$ .

The allowed values go from $l = 0$ to $n-1$ (i.e. $l = 0, 1, 2$ )

(e) 3 1 2

Impossible! You cannot have $m_l = "2"$ .

The allowed values of $m_l$ go from $"-"l$ to $"+"l$ (i.e. $m_l = -1, 0, 1$ ).