Question #c83cc

1 Answer
Apr 11, 2017

#color(blue)(x=84)#

Explanation:

I'm assuming you mean #-6log_3(x-3)=-24#

Divide both sides by #-6#.

#[1]" "-6log_3(x-3)=-24#

#[2]" "(color(red)(cancel(-6))log_3(x-3))/color(red)(cancel(-6))=(color(red)(cancel(-24))4)/color(red)(cancel(-6))#

#[3]" "log_3(x-3)=4#

We will now change this to its equivalent exponential form. Take note that #y=b^x<=>log_by=x#

#[4]" "<=>3^4=x-3#

#[5]" "81=x-3#

#[6]" "81+3=x#

#[7]" "color(blue)(x=84)#