Question #22b27

Question

1344 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-17T22:55:32

The frequency factor is #3.8 × 10^15color(white)(l) "s"^"-1"#.

You have the right equation.

#lnk = -E_text(a)/(RT) + lnA#

# lnA = lnk + E_text(a)/(RT)#

#T = "(325 + 273.15) K" = "598.15 K"#

#lnA = ln(6.1 × 10^"-8") + ("261 000" "J·mol"^"-1")/(8.314 "J·K·mol"^"-1" × 598.15 "K")= "-16.61 + 52.48" = 35.87#

#A = e^35.87 color(white)(l)"s"^"-1" = 3.8 × 10^15color(white)(l) "s"^"-1"#