# Question #37919

Apr 12, 2017

$14 {z}^{3}$

#### Explanation:

$14 {x}^{2} \cdot \frac{{z}^{3}}{x} ^ 2$
$\frac{14 {x}^{2} \cdot {z}^{3}}{x} ^ 2$

When the bases are the same and are being divided, we subtract the exponents

So, $\frac{14 {x}^{2}}{x} ^ 2$ becomes just $14$

That leaves us with $14 \cdot {z}^{3}$