# Question #004f2

Apr 12, 2017

0.56

#### Explanation:

1 molar solution =$\text{Number of moles of solute"/"Volume of solution}$
for Sugar
${C}_{12} {H}_{22} {O}_{11}$ molar mass=342$g m$
according to equation and information provided
$1 = \frac{\frac{3.42}{342}}{x}$
where x is the volume of solution in $l$
$\therefore$ the volume of solution is 0.01 $l$
which is 10 $m l$
$\therefore$10 gm of water .
moles of solute=$\frac{3.42}{342} = 0.01$
moles of solution =$\frac{10}{18} = 0.55$
$\therefore$ the mole fraction of the solution is $\frac{0.01}{0.01 + 0.55}$