Question #17639

1 Answer
Apr 12, 2017

Answer:

I'll show you!

Explanation:

For convenience, I will use kPa rather than mmHg. But that is a mere preference (and I will walk you through the same calculations using mmHg in the second part):

You should already know the relationship between volume and pressure:

#Valpha1/p#

You may also know that:

#P_1V_1=P_2V_2# <- This essentially means, that the initial conditions the final conditions

So, what do we know from the question?
#P_1=100kPa#
#V_1=2.5dm^3# (i.e. L)
#P_2=66.66kPa#

Hence:
#100*2.5=66.66*V_2#
#V_2=3.75dm^3# (i.e. L)

The same thing is also true if you use mmHg:

#P_1=750mmHg#
#V_1=2.5dm^3# (i.e. L)
#P_2=500mmHg#

Hence:
#750*2.5=500*V_2#
#V_2=3.75dm^3# (i.e. L)

Hope it helped :)