# Question #48107

Apr 13, 2017

Here's what I get.

#### Explanation:

As a weak base, ${\text{CH"_3"NH}}_{2}$ in involved in an equilibrium reaction with water.

It removes a proton from the water, converting the water to its conjugate base, $\text{OH"^"-}$.

The equation is

$\underbrace{\text{CH"_3"NH"_2"(aq)")_color(red)("base") + underbrace("H"_2"O(l)")_color(red)("acid") ⇌ underbrace("CH"_3"NH"_3^"+""(aq)")_color(red)("conjugate acid") + underbrace("OH"^"-""(aq)")_color(red)("conjugate base}}$