Question #1125a

1 Answer
Apr 13, 2017

Answer:

Assumption: The question should be #(x^2+13x+36)/(x+4)#

The answer for this is #x+9#

Explanation:

#color(blue)("Answering the question")#

When faced with one of these it is always worth checking if the denominator is an exact factor of the numerator. If so then you can simplify by cancelling out.

The constant in the denominator is 4. So the relation ship between 4 and the 36 in the numerator is #4xx9=36#

Note that #9+4=13# so are 'on a winner' with this check.

Set as:#" "((x+4)(x+9))/(x+4) " "->" "(cancel((x+4))(x+9))/(cancel(x+4)) = x+9#
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#color(blue)("Note about formatting in Socratic.")#

Any maths 'bits' should start and end with the hash symbol

You can group terms by brackets to apply the formatting required.

For this question I used:

#color(green)("hash(x^2+13x+36)/(x+4)hash to give "(x^2+13x+36)/(x+4))#

Notice that one set of brackets group the numerator and a separate set of brackets groups the denominator.

Another example: hash sqrt(3x+1)-10 hash gives #sqrt(3+1)-10#

Notice that the brackets group that which is be square rooted.